CIV E 444 - APPLIED HYDRAULICS
FALL 2009
HOMEWORK No. 4 SOLUTION

  1. Assume critical flow.

    yc = [q2/g]1/3

    yc = [502/9.81]1/3

    yc = 6.34 m.

    vc = q/yc = 50/6.34 = 7.886 m/s

  2. Q = C L H3/2

    Q = 1.45 × (8000 × 0.3048 m/ft) × (18.899 - 18.684)   3/2

    Q = 1.45 × 2438.4 × (0.215)  3/2

    Q = 352.48 m3/s at the design head.

  3. Use ONLINE CHANNEL 05 to calculate critical and normal depth, with Q = 10 m3, b = 1.5 m, z = 1, S = 0.0006, and n = 0.013.

    yc = 1.251 m.

    yn = 1.763 m.

    vc = 2.905 m/s.

    vn = 1.739 m/s.

  4. Use available formulas for and iterative method for the hydraulic jump:

    q = 1.25 m2/s

    y1 = 0.2 m.

    v1 = 6.25 m/s.

    F1 = 4.462

    y2 = 1.166 m.

    v2 = 1.072 m/s.

    F2 = 0.316

    ΔE = 0.966 m.