Find the friction factor f:
f = fD / 8 = 0.032 / 8 = 0.004
So = f F12
F12 = So / f = 0.03 / 0.004 = 7.5
F1 = 2.74 ANSWER.
F12 = v2/(gy1) = q2/(gy13) = 7.5
y1 = [q2/(7.5 g)]1/3 = [(2.8)2 /(7.5 × 9.81)]1/3 = 0.474 m.
ANSWER.
F22 = v2/(gy2) = q2/(gy23) = 1
y2 = [q2/g]1/3 = [(2.8)2 / 9.81]1/3 = 0.928 m.
ANSWER.
Δx = Δy / So = (y2 - y1) / So = (0.928 - 0.474) / 0.004
Δx = 113.5 m. ANSWER.
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