CIV E 530 - OPEN-CHANNEL HYDRAULICS

SPRING 2007 - MIDTERM 2 - SOLUTION

PROBLEM 2

    1. So = Sc F12

      F12 = So / Sc = 0.0045 / 0.0045 = 1

      F1 = 1   ANSWER.

    2. F12 = v2/(gy1) = q2/(gy13) = 1

      y1= (q2/g)1/3 = (12/9.81)1/3 = 0.467 m.    ANSWER.

    3. v12/(gy1) = 1

      v1= (gy)1/2 = (9.81 × 0.467)1/2 = 2.14 m/s    ANSWER.

    4. Because the u/s flow is critical, the water-surface flow profile type is C1.    ANSWER.
    5. So = Δy/Δx

      Δx = Δy / So = (y2 - y1) / So = (2.4 - 0.467) / 0.0045 = 429.55 m.    ANSWER.

Problem 3

 
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