CIV E 530 - OPEN-CHANNEL HYDRAULICS

SPRING 2017 - MIDTERM 2 - SOLUTION

PROBLEM 1

  • So = f F12

    F12 = So / f = 0.0035 / 0.0035 = 1

    F1 = 1   ANSWER.

  • F12 = v2/(gy1) = q2/(gy13) = 1

    y1 = (q2/g)1/3 = (0.42/9.81)1/3 = 0.254 m.    ANSWER.

  • v1 = q / y1 = 0.4 / 0.254 = 1.57 m/s    ANSWER.

  • So = Δy/Δx

    Δx = Δy / So = (y2 - y1) / So = (1.50 - 0.254) / 0.0035

    Δx = 356 m.    ANSWER.

Problem 2

 
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