CIV E 530 - OPEN-CHANNEL HYDRAULICS

FALL 2005 - MIDTERM 2 - SOLUTION

PROBLEM 1

yc = (q2/g)1/3

qmax = 50 m3/s/m

yc = (q2/g)1/3 = (502/9.81)1/3

yc = 6.34 m.

PROBLEM 2

Q = C L H3/2 = 3.09 L H3/2

Q = 3.09 × 20 × (0.8)3/2

yc = 44.22 cfs.

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C = 2/3 [(2/3)g]1/2

C = 2/3 [(2/3) × 32.17 ]1/2 = 3.087

 
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