CIV E 530 - OPEN-CHANNEL HYDRAULICS

SPRING 2014 - MIDTERM 1 - SOLUTION

PROBLEM 1

So = 1.0 / 0.6 = 1.667

fD = 0.032

f = fD / 8 = 0.004

So = f F2

F2 = So / f = 1.667 / 0.004 = 416.75

F = 20.4

The maximum value of Froude number cannot go much higher than 20, maybe around 25.   ANSWER.

Problem 2

 
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