The calculations are shown in the
following table.
[1] |
[2] |
[3] |
[4] |
[5] |
[6] |
[7] |
Time (h) |
Flow (m3/s) |
Baseflow (m3/s) |
Direct runoff hydrograph (m3/s) |
Simpson's coefficients |
Direct runoff volume computation (m3/s) |
Unit hydrograph ordinates (m3/s) |
0 |
1 |
1 |
0 |
1 |
0 |
0.00 |
1 |
2 |
1 |
1 |
4 |
4 |
1.67 |
2 |
4 |
1 |
3 |
2 |
6 |
5.00 |
3 |
8 |
1 |
7 |
4 |
28 |
11.67 |
4 |
12 |
1 |
11 |
2 |
22 |
18.33 |
5 |
8 |
1 |
7 |
4 |
28 |
11.67 |
6 |
7 |
1 |
6 |
2 |
12 |
10.00 |
7 |
6 |
1 |
5 |
4 |
20 |
8.33 |
8 |
5 |
1 |
4 |
2 |
8 |
6.66 |
9 |
4 |
1 |
3 |
4 |
12 |
5.00 |
10 |
3 |
1 |
2 |
2 |
4 |
3.33 |
11 |
2 |
1 |
1 |
4 |
4 |
1.67 |
12 |
1 |
1 |
0 |
1 |
0 |
0.00 |
Sum (Σ) |
- |
- |
50 |
- |
148 |
83.33 |
Direct runoff hydrograph: Col. 4 = Col. 2 - Col. 3
Direct runoff volume computation: Col. 6 = Col. 4 × Col. 5
Direct runoff volume, by Simpson's rule: [(1 h × 3,600 s/h) / 3 ] × 148 = 177,600 m3
Direct runoff depth: [177,600 m3 / (29.6 km2 × 1,000,000 m2/km2] = 0.006 m = 0.6 cm
Unit hydrograph ordinates: Col. 4 / 0.6 cm
The sum of Col. 7 is 83.33.
Verification: Σ Col. 4 / 0.6 = 50 / 0.6 = 83.33
Thus, it is verified that Col. 7 is a unit hydrograph, containing 1 cm of runoff.